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Home/ Questions/Q 8391691
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T19:19:37+00:00 2026-06-09T19:19:37+00:00

How can I render a partial view to be used in a JsonResult in

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How can I render a partial view to be used in a JsonResult in a controller?

return Json(new
{
    Html = this.RenderPartialView("_EditMovie", updatedMovie),
    Message = message
}, JsonRequestBehavior.AllowGet);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T19:19:38+00:00Added an answer on June 9, 2026 at 7:19 pm

    RenderPartialView is a custom extension method which renders a view as a string.

    It wasn’t mentioned in the article (what you have referred originally) but you find it in the sample code attached to the article.
    It can be found under the \Helpers\Reders.cs

    Here is code of the method in question:

    public static string RenderPartialView(this Controller controller, 
        string viewName, object model)
    {
        if (string.IsNullOrEmpty(viewName))
            viewName = controller.ControllerContext.RouteData
                .GetRequiredString("action");
    
        controller.ViewData.Model = model;
        using (var sw = new StringWriter())
        {
            ViewEngineResult viewResult = ViewEngines.Engines
                .FindPartialView(controller.ControllerContext, viewName);
            var viewContext = new ViewContext(controller.ControllerContext, 
                viewResult.View, controller.ViewData, controller.TempData, sw);
            viewResult.View.Render(viewContext, sw);
    
            return sw.GetStringBuilder().ToString();
        }
    }
    
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