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Editorial Team
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Asked: 2026-05-24T23:36:02+00:00

How can I replace all types of line breaks (CR, LF and CrLf) using

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How can I replace all types of line breaks (CR, LF and CrLf) using Regex?

I´ve tried different combinations of “\n” and “\r” but none finds them all.

formatedString = System.Text.RegularExpressions.Regex.Replace(text, "\r\n", "[Exp 1]")

The following code does the job but it bugs me that I can´t seem to replace the Line Feed using Regexp.

formatedString = formatedString.Replace(Environment.NewLine, "[Environment.NewLine]") ' Equals CR
formatedString = formatedString.Replace(ControlChars.CrLf, "[ControlChars.CrLf]") ' CR and LF
formatedString = formatedString.Replace(ControlChars.Cr, "[ControlChars.Cr]") ' Carriage Return (CR)
formatedString = formatedString.Replace(ControlChars.Lf, "[ControlChars.Lf]") ' Line Feed (LF)

All advices are most welcome! 🙂

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1 Answer

  1. Editorial Team

    \r, \n and \r\n should cover all cases of linebreaks. \n\r is not used by any system (that I know of…)

    In VB, if not using regexes, you could replace all:

    VbCr
VbLf
VbCrLf

    with whatever line ending you prefer (obviously you can omit the preferred one from the list of “newline/cr” characters you replace)

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