Question

How can I return the result of a different action or move the user to a different action if there is an error in my ModelState without losing my ModelState information?

The scenario is; Delete action accepts a POST from a DELETE form rendered by my Index Action/View. If there is an error in the Delete I want to move the user back to the Index Action/View and show the errors that are stored by the Delete action in the ViewData.ModelState. How can this be done in ASP.NET MVC?

[AcceptVerbs(HttpVerbs.Post | HttpVerbs.Delete)] public ActionResult Delete([ModelBinder(typeof(RdfUriBinder))] RdfUri graphUri) {     if (!ModelState.IsValid)         return Index(); //this needs to be replaced with something that works :)      return RedirectToAction("Index"); } 

Answer 1

Store your view data in TempData and retrieve it from there in your Index action, if it exists.

   ...    if (!ModelState.IsValid)        TempData["ViewData"] = ViewData;     RedirectToAction( "Index" ); }   public ActionResult Index()  {      if (TempData["ViewData"] != null)      {          ViewData = (ViewDataDictionary)TempData["ViewData"];      }       ...  } 

[EDIT] I checked the on-line source for MVC and it appears that the ViewData in the Controller is settable, so it is probably easiest just to transfer all of the ViewData, including the ModelState, to the Index action.