Question

how can i round up a floating point number to the next integer value in Java? Suppose

2.1 –>3

3.001 –>4

4.5 –>5

7.9 –>8

Answer 1

You should look at ceiling rounding up in java’s math packages: Math.ceil

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EDIT: Added the javadoc for Math.ceil. It may be worth reading all the method in Math.

http://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#ceil%28double%29

public static double ceil(double a)

Returns the smallest (closest to negative infinity) double value that
is greater than or equal to the argument and is equal to a
mathematical integer. Special cases:

• If the argument value is already equal to a mathematical integer, then the result is the same as the argument.
• If the argument is NaN or an infinity or positive zero or negative zero, then the result is the same as the argument.
• If the argument value is less than zero but greater than -1.0, then the result is negative zero.

Note that the value of Math.ceil(x) is exactly the value of
-Math.floor(-x).