Question

How can I run a batch file and pass parameters to jar file?

this doesn’t work

mybat.bat

java -jar log_parser.jar %1 %2 %3 %4

running bat file

C:\>log_parser.bat -file=C:\\trace_small.log -str=Storing

java sees only -file

Answer 1

I just tried with a small java program that only dumps the arguments to the screen:

public static void main(String[] args)
{
    for(String s : args)
    {
        System.out.println(s);
    }
}   

and the following batch file :

java -jar test.jar %1 %2 %3 %4

and I ended up with the following result

-file
C:\\trace_small.log
-str
Storing

For the same command line as you… the equal sign ‘=’ desapeared.
Now if you trun the batch file to this :

java -jar test.jar %*

you will get yet another result (which might be what you expected – not clear)

-file=C:\\trace_small.log
-str=Storing

The advantage on this %* syntax, is that it is more extensible by accepting any number of arguments.

Hope this helps, but I recommend you to have a look at your code to and add some debug statement to understand where you are “lossing” some part of the input.