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Home/ Questions/Q 6092005
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:23:35+00:00 2026-05-23T12:23:35+00:00

How can I run a function on checkbox change? I’m trying to write small

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How can I run a function on checkbox change?

I’m trying to write small checkbox replacing function base on that – but I’m doing something wrong.

Code:

(function($) {
    $.fn.checking = function() {
        if ($('.checbox').prop('checked', false) === true) {
            $('.new-checkbox').prop('id', 'unchecked');
        } else {
            $('.new-checkbox').prop('id', 'checked');
        }
    };
})(jQuery);


$(document).ready(function() {

    $('.checkbox').wrap('<div class="checkbox-wrapper"></div>');
    $('.checkbox-wrapper').append('<p class="new-checkbox">Blue = Checked, Red = Unchecked</p>');
    $('.checkbox').checking();
    $('.checbox').bind('change', function() {
        $(this).checking();

    });

});

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:23:36+00:00Added an answer on May 23, 2026 at 12:23 pm

    You have some typos and errors in your script.

    if($('.checbox').prop('checked', false) === true)
    //         ^                   ^^^^^^^^^^^^^^^^^
    

    should be

    if(this.prop('checked'))
    

    if($('.checkbox').prop('checked')) would work too of course, but why select the element again, if you already made it a plugin and the element is available via this?

    And

    $('.checbox').bind('change', function(){
    //      ^
    

    should be

    $('.checkbox').bind('change', function(){
    //      ^
    

    Working demo: http://jsfiddle.net/fkling/yGBAK/40/

    That said, it is better (more logical) to add and remove a class than changing the ID of the element.

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