Question

How can I show something on 75% of requests, so that on average, every four page requests would result in three pages showing it, and one not.

this is a translation of this question!…

i dont know how it working with 70%

now how i can show in example echo
iam; in a page in 70% percent

this mean it will appear 3 times and
one not

Answer 1

The only fool proof way I can think to do this is:

if (($pageHits % 10) < 7)
    echo 'iam';