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Home/ Questions/Q 9235919
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T07:09:59+00:00 2026-06-18T07:09:59+00:00

How can I specialize a class template so that the template parameters can be

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How can I specialize a class template so that the template parameters can be of type : a pointer to a particular class or a pointer to the derived class of that particular type? Is it possible to do it without using Boost?

Possible Duplicate of: C++ templates that accept only certain types

I just wanted to know whether the answer is same even if I am using a pointer to the instances .

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  1. Editorial Team
    Editorial Team
    2026-06-18T07:10:00+00:00Added an answer on June 18, 2026 at 7:10 am

    You could specialize your class for pointers and then use std::is_base_of with a static_assert:

    template <typename T>
    class foo;
    
    template <typename T>
    class foo<T*>
    {
      static_assert(std::is_base_of<Base, T>::value, "Type is not a pointer to type derived from Base");
    };
    

    See it in action. Both std::is_base_of and static_assert are C++11 features so no Boost is required.

    If for some reason you don’t like static_assert, you could do it the enable_if way:

    template <typename T, typename Enable = void>
    class foo;
    
    template <typename T>
    class foo<T*, typename std::enable_if<is_base_of<Base, T>::value>::type>
    {
      // ...
    };
    
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