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Home/ Questions/Q 3848012
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T16:38:19+00:00 2026-05-19T16:38:19+00:00

how can I split a list(e.g. 24 entries) into several parts(each containing max. 10

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how can I split a list(e.g. 24 entries) into several parts(each containing max. 10 entries) and cover the last entries?

What I have done so far:

 //init list
    List<Integer> list = new ArrayList<Integer>();
    for (int i = 0; i < 24; i++) {
        list.add(i);
    }

    List<Integer> splitted = new ArrayList<Integer>();
    for (int i = 0; i < list.size(); i++) {
        splitted.add(list.get(i));
        if(i != 0 && i % 10 == 0) {
            //print splitted list
            System.out.println(splitted);
            splitted.clear();
        }
    }

That works for the entries 0-20 but the entries 21,22,23 and 24 will not appear in any list. How can I fix this? Because i % 10 == 0 won’t work for them.

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  1. Editorial Team
    Editorial Team
    2026-05-19T16:38:19+00:00Added an answer on May 19, 2026 at 4:38 pm

    This should work or at leart give you some idea. What I do is first check whether list is finished or splitted reached 10. Then check if i is not equal to 0 and print splitted.

    for (int i = 0; i < list.size(); i++) {
        splitted.add(list.get(i));
        if(i==list.size()-1 || i%10==0) {
           if(i!=0){
              //print splitted list
               System.out.println(splitted);
               splitted.clear();
           }
        }
    }
    
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