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Home/ Questions/Q 395247
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T16:26:06+00:00 2026-05-12T16:26:06+00:00

How can I use php to determine which files are invoked and included given

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How can I use php to determine which files are invoked and included given a url only.

eg. the URL, http://www.mydomain.com/index.php

might use:

  • index.php
  • includes.php
  • content.html

I want to give php the url and it return the filenames.

Thank you 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-12T16:26:06+00:00Added an answer on May 12, 2026 at 4:26 pm

    You’re not going to be able to do this from a URL. To the outside world a URL is just something that returns a bunch of text. There’s little to nothing that can be done to devine how that text was created.

    If you have access to the source code, placing this at the end of your entry file will be a big help.

    print_r(get_included_files());
    

    This will print out every file that’s been included or required in. However, this won’t give you any file that’s been accessed with fopen, file_get_contents, etc. If you’re interested in seeing if a particular file has been accessed or not, the unix stat program can tell you this. However, in normal computer operation files are accessed for lots of different reasons, so you’ll want to be careful relying on anything that comes out of stat.

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