Question

How can I use preg_replace to remove everything after a keyword is matched?

For instance, if the keyword local is matched in the string below,

home/hello/local/flower/stone/...

then return this only,

home/hello

or can I use any php default array function?

Answer 1

Depending on what you want to do, a simple strpos + strlen could do the trick.

<?php

$string = "hello/local/flower/stone/...";
$keyword = "local";

echo substr($string, 0, strpos($string, $keyword));

?>

http://ideone.com/3OOq8

Be careful, I assumed that you’ll always have your keyword in the String, that might not be the case.

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Resources:

• php.net – strpos()
• php.net – strlen()
• php.net – substr()