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Home/ Questions/Q 7248793
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T22:11:16+00:00 2026-05-28T22:11:16+00:00

How can i use this function always but only extend the success: function.. to

  • 0

How can i use this function always but only extend the success: function.. to my seperate callback?

global.js

// one time written and will be uesd 100 times without re-write the same thing.
function useEveryWhere(url, par) {
    $.ajax({
      type: "POST",
      dataType: "json",
      url: url, //PHP call
      data: par,
      async: true,
      success : function(msg) {}            
    }); 
}

anotherpage1.js

// Here i need the success: function with different task 
ueEveryWhere(url, parameters); 

anotherpage2.js

// Here i need the success: function with different task too not same as anotherpage1.js
ueEveryWhere(url, parameters); 

How do i have that global.js success method in any other scripts too, where i have random task not all are same.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T22:11:17+00:00Added an answer on May 28, 2026 at 10:11 pm

    You can use the ajaxSucess function to specify a global sucess method, and change useEveryWhere to accept a success function:

    function useEveryWhere(url, par, sucess) {
        $.ajax({
          type: "POST",
          dataType: "json",
          url: url, //PHP call
          data: par,
          async: true,
          success : sucess      
        }); 
    }
    

    anotherpage1.js

    useEveryWhere(url, parameters, function() { ... }); 
    

    anotherpage2.js

    useEveryWhere(url, parameters, function() { ... }); 
    
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