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Home/ Questions/Q 497319
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:46:12+00:00 2026-05-13T05:46:12+00:00

How can one portably perform pointer arithmetic with single byte precision? Keep in mind

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How can one portably perform pointer arithmetic with single byte precision?

Keep in mind that:

  • char is not 1 byte on all platforms
  • sizeof(void) == 1 is only available as an extension in GCC
  • While some platforms may have pointer deref pointer alignment restrictions, arithmetic may still require a finer granularity than the size of the smallest fundamental POD type
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  1. Editorial Team
    Editorial Team
    2026-05-13T05:46:12+00:00Added an answer on May 13, 2026 at 5:46 am

    Your assumption is flawed – sizeof(char) is defined to be 1 everywhere.

    From the C99 standard (TC3), in section 6.5.3.4 (“The sizeof operator”):

    (paragraph 2)

    The sizeof operator yields the size
    (in bytes) of its operand, which may
    be an expression or the
    parenthesized name of a type.

    (paragraph 3)

    When applied to an operand that has
    type char, unsigned char, or signed
    char, (or a qualified version
    thereof) the result is 1.

    When these are taken together, it becomes clear that in C, whatever size a char is, that size is a “byte” (even if that’s more than 8 bits, on some given platform).

    A char is therefore the smallest addressable type. If you need to address in units smaller than a char, your only choice is to read a char at a time and use bitwise operators to mask out the parts of the char that you want.

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