Question

How can you pass parameters to a function when using .call() in Javascript?

When I pass parameters they are always undefined in the callback function

EDIT (an example):

I will have an options object in my plugin:

var options = {

errorCallback : function( errors ) {}

}

I will call this from my plugin like this:

var errors = "Test error list";
configs.errorCallback.call(errors);

I will initialise my plugin like this

 $('#plugin-element').myPlugin(
       { 
           'errorCallback' : function errorrCallbackFunction( errors ) {
                   console.log(errors) //always undefined
               }
       }

Answer 1

The first argument of call is the ‘this’ of the function. If you want to pass the variable as argument start from the second one.

configs.errorCallback.call(undefined, errors);

Here is the documentation: Function.prototype.call()