Question

How can you specify cross-browser transform controls using jQuery since each browser seems to use its own methodology?

Here is the code I am using for Firefox but I can’t even get it to work. I think it’s because there is no way to tell which transformation – scale, rotate, skew – to use.

$(".oSlider-rotate").slider({
     min: 10,
     max: 74,
     step: .01,
     value: 24,
     slide: function(e,ui){
                 $('.user-text').css('transform', ui.value)

            }                
  });

Answer 1

If you want to use a specific transform function, then all you need to do is include that function in the value. For example:

$('.user-text').css('transform', 'scale(' + ui.value + ')');

Secondly, browser support is getting better, but you’ll probably still need to use vendor prefixes like so:

$('.user-text').css({
  '-webkit-transform' : 'scale(' + ui.value + ')',
  '-moz-transform'    : 'scale(' + ui.value + ')',
  '-ms-transform'     : 'scale(' + ui.value + ')',
  '-o-transform'      : 'scale(' + ui.value + ')',
  'transform'         : 'scale(' + ui.value + ')'
});

jsFiddle with example: http://jsfiddle.net/jehka/230/