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Home/ Questions/Q 255879
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:58:02+00:00 2026-05-11T21:58:02+00:00

How come dividing two 32 bit int numbers as ( int / int )

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How come dividing two 32 bit int numbers as ( int / int ) returns to me 0, but if I use Decimal.Divide() I get the correct answer? I’m by no means a c# guy.

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:58:03+00:00Added an answer on May 11, 2026 at 9:58 pm

    int is an integer type; dividing two ints performs an integer division, i.e. the fractional part is truncated since it can’t be stored in the result type (also int!). Decimal, by contrast, has got a fractional part. By invoking Decimal.Divide, your int arguments get implicitly converted to Decimals.

    You can enforce non-integer division on int arguments by explicitly casting at least one of the arguments to a floating-point type, e.g.:

    int a = 42;
    int b = 23;
    double result = (double)a / b;
    
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