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Home/ Questions/Q 4114868
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T22:30:36+00:00 2026-05-20T22:30:36+00:00

How come my if statement if (tablename == Character.toString(‘S’)) is not registering as true?

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How come my if statement if (tablename == Character.toString('S')) is not registering as true? Both print out the be S… Is there a different why I can implement this? I could do a != but I need to add more arguments to my if statement, and my tablename needs to stay a string.

System.out.println("Enter table:");
String line = input.readLine();
StringTokenizer tk = new StringTokenizer(line);
String tablename = tk.nextToken();

DatabaseMetaData d = conn.getMetaData();
ResultSet rm = d.getColumns(null, null, tablename, null);

System.out.println(tablename);
System.out.println(Character.toString('S');
 System.out.println(tablename == Character.toString('S');

if (tablename == Character.toString('S')){
  System.out.println("Woot!");
}

OUTPUT:
Enter table:
S
S
S
false

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  1. Editorial Team
    Editorial Team
    2026-05-20T22:30:36+00:00Added an answer on May 20, 2026 at 10:30 pm

    Since you’re comparing both objects for equality, you need to use:

    if (tablename.equals(Character.toString('S'))) {
       ...
    

    Here’s a nice reference on equality comparison in java:

    http://leepoint.net/notes-java/data/expressions/22compareobjects.html

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