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Home/ Questions/Q 6223235
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T08:27:13+00:00 2026-05-24T08:27:13+00:00

How could this code throw a null pointer exception? for (Foo f : Vector<Foo>

  • 0

How could this code throw a null pointer exception?

for (Foo f : Vector<Foo> v)
{
    f.doStuff(); // this line throws a NullPointerException
}

Even if the Vector is empty, shouldn’t the inside block just never be executed?

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  1. Editorial Team
    Editorial Team
    2026-05-24T08:27:13+00:00Added an answer on May 24, 2026 at 8:27 am

    The Vector is not empty. As you say, if it was then the loop body would not be executed.

    If you get an NPE on that line, it means that one (or more) of the elements of the Vector is null.


    I should also point out that the example code is syntactically incorrect. It should probably read something like this:

    Vector<Foo> v = ...    
    for (Foo f : v)
    {
        f.doStuff(); // this line throws a NullPointerException
    }
    
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