Question

How could you read this dataset in R, the problem is
that the numbers are floats and are like 4,000000059604644E+16
and they are separated by a ,

4,000000059604644E-16 ,  7,999997138977056E-16,   9,000002145767216E-16
4,999999403953552E-16 ,  6,99999988079071E-16 ,   0,099999904632568E-16
9,999997615814208E-16 ,  4,30000066757202E-16 ,   3,630000114440918E-16
0,69999933242798E-16  ,  0,099999904632568E-16,  55,657576767799999E-16 
3,999999761581424E-16,   1,9900000095367432E-16,  0,199999809265136E-16

How would you load this kinf of dataset in R so it has 3 columns.

If I do

dataset <- read.csv("C:\\data.txt",header=T,row.names=NULL)

it would return 6 columns instead 3…

Answer 1

It might be best to transform that input data to use decimal points, rather than commas, in the floating point numbers. One way you could do this is to use sed (it looks like you are using Windows, so you would likely need to sed to use this approach):

sed 's/\([0-9]\),\([0-9]\)/\1.\2/g' data.txt  > data2.txt

File data2 looks like this:

4.000000059604644E-16 ,  7.999997138977056E-16,   9.000002145767216E-16
4.999999403953552E-16 ,  6.99999988079071E-16 ,   0.099999904632568E-16
9.999997615814208E-16 ,  4.30000066757202E-16 ,   3.630000114440918E-16
0.69999933242798E-16  ,  0.099999904632568E-16,  55.657576767799999E-16 
3.999999761581424E-16,   1.9900000095367432E-16,  0.199999809265136E-16

Then in R:

dataset <- read.csv("data2.txt",row.names=NULL)