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Home/ Questions/Q 565081
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:50:04+00:00 2026-05-13T12:50:04+00:00

How do I animate between two PNG images in jQuery? Is this possible? Something

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How do I animate between two PNG images in jQuery? Is this possible?

Something like the CSS 3 transition when you transit between one color to another, but I need an image to an image transition.

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:50:05+00:00Added an answer on May 13, 2026 at 12:50 pm

    Check out this plugin by Jack Moore called jQuery Blend.

    Edit: Opps two images, sorry. How about this plugin then?


    Ok, if you aren’t happy with a plugin then try this. I posted a demo here.

    CSS/HTML

    <style type="text/css">
    .wrap {
     margin: 50px auto;
     width: 200px;
     height: 200px;
     background: #555;
     position: relative;
    }
    .display1, .display2 {
     position: absolute;
     top: 0;
     left: 0;
    }
    </style>
    <div class="wrap">
     <div class="display1"></div>
     <div class="display2"></div>
    </div>
    

    Script

    $(document).ready(function(){
     var bkgImgs = ([
      ['http://i50.tinypic.com/2iiz9cm.gif', 86, 86],
      ['http://i45.tinypic.com/dop26e.png', 128, 128],
      ['http://i48.tinypic.com/xcosnq.png', 64, 64]
     ]);
     var delay = 5000;
     var transition = 1000;
    
     var i = 0;
     var l = bkgImgs.length-1;
     imgs = function(x){
      return {
       background: 'url(' + bkgImgs[x][0] + ') no-repeat center center',
       width:      bkgImgs[x][1],
       height:     bkgImgs[x][2],
       left:       $('.wrap').width()/2 - bkgImgs[x][1]/2,
       top:        $('.wrap').height()/2 - bkgImgs[x][2]/2
      }
     }
     next = function(){
      var oldpic = imgs(i);
      i++;
      if (i > l) i = 0;
      var newpic = imgs(i);
      $('.display2').css(oldpic).show();
      $('.display1').hide().css(newpic).fadeIn(transition);
      $('.display2').fadeOut(transition);
      setTimeout( function(){ next() }, delay );
     }
     next();
    })
    
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