How do I assign a string to a character pointer in C ?
Suppose I have a string like “1234788654446” and when I assign it to a char pointer, I am getting error like “missing terminating character”. What’s wrong with the following code ?
The actual problem statement is this : I have a 1000 digit number and i have to find the greatest product of 5 consecutive digits. so when i store the number in a string, I am getting warning: “”Integer constant is too large for its type” and error “Invalid digit 9 in octal constant” .
My code is :
#include<stdio.h>
int main(){
int i=0;
int a,b,c,d,e,pro,max=0;
char str[] = "73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450";
while(str[i+4] !='\0'){
a = str[i]-'0';
b = str[i+1]-'0';
c = str[i+2]-'0';
d = str[i+3]-'0';
e = str[i+4]-'0';;
pro = a*b*c*d*e;
if(pro>max)
max = pro;
i++;
}
printf("%d",max);
return 0;
}
Line breaks aren’t your friend. You need to do …
(Notice the
\on the end of each line, and no leading whitespace on subsequent lines. You can’t split a quoted string over multiple lines in C without using\)Option B is: