Question

How do I call a method when both checkboxes are ticked in php?

if (isset($_POST['check1'])) 
{data1();}

else if (isset($_POST['check2']) 
{data2();}

The above works perfectly for single checkboxes. The moment I tick both it only brings up data1(). I tried the following.

else if(isset($_POST['check1']) && ($_POST['check2'])) 
{data1and2();}

and

else if(isset($_POST['check1']) && ($_POST['check2']))
{data1and2();}   

Answer 1

You missed isset for $_POST['check2']

 if(isset($_POST['check1']) && isset($_POST['check2'])) {
    data1and2();
 }

And this condition should be first.

 if(isset($_POST['check1']) && isset($_POST['check2'])) {
    data1and2();
 } else if (isset($_POST['check1'])) {
    data1();
 } else if (isset($_POST['check2'])) {
    data2();
 }