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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T08:16:32+00:00 2026-05-13T08:16:32+00:00

How do I check for EOF in Python? I found a bug in my

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How do I check for EOF in Python? I found a bug in my code where the last block of text after the separator isn’t added to the return list. Or maybe there’s a better way of expressing this function?

Here’s my code:

def get_text_blocks(filename):
    text_blocks = []
    text_block = StringIO.StringIO()
    with open(filename, 'r') as f:
        for line in f:
            text_block.write(line)
            print line
            if line.startswith('-- -'):
                text_blocks.append(text_block.getvalue())
                text_block.close()
                text_block = StringIO.StringIO()
    return text_blocks
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T08:16:33+00:00Added an answer on May 13, 2026 at 8:16 am

    You might find it easier to solve this using itertools.groupby.

    def get_text_blocks(filename):
        import itertools
        with open(filename,'r') as f:
            groups = itertools.groupby(f, lambda line:line.startswith('-- -'))
            return [''.join(lines) for is_separator, lines in groups if not is_separator]
    

    Another alternative is to use a regular expression to match the separators:

    def get_text_blocks(filename):
        import re
        seperator = re.compile('^-- -.*', re.M)
        with open(filename,'r') as f:
            return re.split(seperator, f.read())
    
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