Question

How do I convert string into integers in this dictionary then loop through it without getting errors like invalid literal for int() with base 10 🙁

mydict = {('6.0', '1.0'): '345.2', ('3.0', '9.0'): '632.7',
    ('2.0', '3.0'): '222.4', ('1.0', '4.0'): '672.1', ('8.0', '6.0'): '822.6',
    ('3.0', '8.0'): '225.5', ('7.0', '7.0'): '534.0', ('4.0', '7.0'): '599.3',
    ('8.0', '9.0'): '273.5', ('5.0', '3.0'): '822.5', ('4.0', '2.0'): '326.6'}

in which (key1, key2): value

I would also like to loop through this dictionary, and calculate using this formula…

((key1 * 360 / key2 * 180) + value)

for each key pair. Then, I would print out the 3 largest value resulted from the calculation. Is this possible?

Answer 1

You can do the following:

res = map(lambda x: (float(x[0][0]) * 360.) / (float(x[0][1]) * 180.) + float(x[1]), mydict.items())

That will produce something like :

[357.2, 633.37]

To get the 3 largest:

sorted(res, reverse=True)[0:3]

Hope that helps.