Question

How do I display ajax response of my code? When I used async=true the yy value shown is only the last value; I need to show it for all value from 0 to a. It works fine with async=false. Here is my code:

for(var jj=0;jj<a;jj++){
                var yy=jj;
                var ins=12
                var rou=13
                /* */
                $.ajax({
                            type:"GET",
                             url:"Select.php",
                             async:false,
                             data:"rou="+rou+
                                 "&ins="+ins,   

                           success : function(t){

                            $("#truk"+yy).text(t);
                            // Response not shown here


                          } //success
                 });              

               }    

Answer 1

But anyway it is the result of the ajax call what you are searching for:

var syncResult = $.ajax('/echo/json/', {
    async: false
});
document.write(syncResult.responseText);

See it live here: http://jsfiddle.net/alligator/6MsuZ/