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Home/ Questions/Q 4266114
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T06:42:58+00:00 2026-05-21T06:42:58+00:00

How do I ensure that there are no unexpected functions inherited from the parent

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How do I ensure that there are no unexpected functions inherited from the parent when my script is run? If using bash,

#!/bin/bash -p

will do the trick, as will invoking the script through env -i. But I cannot rely on the user to invoke env, I don’t want to rely on bash, I don’t want to do an exec-hack and re-exec the script, and

#!/usr/bin/env -i sh

does not work.

So I’m looking for a portable way (portable == posix) to ensure that the user hasn’t defined functions that will unexpectedly modify the behavior of the script. My current solution is:

eval $( env | sed -n '/\([^=]*\)=(.*/s//\1/p' |
    while read -r name; do echo unset -f $name\;; done )

but that’s pretty ugly and of dubious robustness. Is there a good way to get the functionality that ‘unset -f -a’ should provide?

edit

Slightly less ugly, but no better (I don’t like parsing the output of env):

unset -f $( env | sed -n '/\([^=]*\)=(.*/s//\1/p' | tr \\012 \  )
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T06:42:59+00:00Added an answer on May 21, 2026 at 6:42 am
    #!/bin/bash --posix 
    

    results in:

    SHELLOPTS=braceexpand:hashall:interactive-comments:posix
    

    same as:

    #!/bin/sh
    
    SHELLOPTS=braceexpand:hashall:interactive-comments:posix
    

    and “sh” is posix…

    EDIT:

    tested a few functions – unset was not required in my case…

    EDIT2:

    compare output of “set”, not just “env”

    EDIT3:

    the following example – output of both “set|wc” also gives same results:

    #!/bin/sh
    
    set
    set|wc
    
    unset -f $( env | sed -n '/\([^=]*\)=(.*/s//\1/p' | tr \\012 \  )
    
    set
    set|wc
    
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