Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8031765
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 5, 20262026-06-05T01:12:27+00:00 2026-06-05T01:12:27+00:00

How do I escape a wildcard expansion in a variable name? CP=lib/* COMMAND=java $VARIABLES

  • 0

How do I escape a wildcard expansion in a variable name?

CP="lib/*"
COMMAND="java $VARIABLES -cp $CP SomeClass"
echo $COMMAND

Echoing the command always causes wildcard expansion.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-05T01:12:28+00:00Added an answer on June 5, 2026 at 1:12 am
    echo "$COMMAND"
    

    Using quotes prevents the glob from being expanded.

    By the way, see “I’m trying to put a command in a variable, but the complex cases always fail!”

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

How can I escape the wildcard characters in a like clause? E.g.: select foo
I have used escape function of java script to encode a java script string.
The answer to Java escape HTML shows StringUtils.replaceEach() which runs similar to multiple StringUtils.replace()
I would like to match this 'wildcard %' in MySQL. I tried using escape
How do I escape commas in mysql insert statements? mysql> create table test.todel (name
I'm trying to escape characters within backticks in my bash command, mainly to handle
I'm trying to escape a RegExp metacharacter in Java. Below is what I want:
Escape characters cause a lot of trouble in R, as evidenced by previous questions:
cgi.escape seems like one possible choice. Does it work well? Is there something that
How can you escape underscores only in the tabular environment without the use of

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.