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Home/ Questions/Q 6756807
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:34:07+00:00 2026-05-26T13:34:07+00:00

How do I escape the forward slash character in an xpath query? My tags

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How do I escape the forward slash character in an xpath query? My tags contain a url, so I need to be able to do this. I am using lxml in python.

Alternatively, is it possible for xpath to query a substring of the path? Examples are below:

xml="""
<entry xmlns="http://www.w3.org/2005/Atom" xmlns:gsa="http://schemas.google.com/gsa/2007">
  <gsa:content name="reportName">bbb</gsa:content>
  <gsa:content name="collectionName">default_collection</gsa:content>
  <gsa:content name="reportDate">date_3_25_2009</gsa:content>
 </entry>
"""

When I run the following:

tree=fromstring(xml)
for elt in tree.xpath('//*'):
    elt.tag

It returns:

'{http://www.w3.org/2005/Atom}entry'
'{http://schemas.google.com/gsa/2007}content'
'{http://schemas.google.com/gsa/2007}content'
'{http://schemas.google.com/gsa/2007}content'

Running tree.xpath('/entry') returns an empty list.

I need to be able to either query for ‘{http://www.w3.org/2005/Atom}entry’ as the tag, or query for ‘entry’ anywhere in the tag.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:34:08+00:00Added an answer on May 26, 2026 at 1:34 pm

    Look into namespace prefixes[docs].

    If you want an element that’s in the http://schemas.google.com/gsa/2007 namespace you need to search for it like so:

    import lxml.etree as et
    
    xml="""
    <entry xmlns="http://www.w3.org/2005/Atom" xmlns:gsa="http://schemas.google.com/gsa/2007">
      <gsa:content name="reportName">bbb</gsa:content>
      <gsa:content name="collectionName">default_collection</gsa:content>
      <gsa:content name="reportDate">date_3_25_2009</gsa:content>
     </entry>
    """
    
    NS = {'rootns': 'http://www.w3.org/2005/Atom',
          'gsa': 'http://schemas.google.com/gsa/2007'}
    
    tree = et.fromstring(xml)
    
    for el in tree.xpath('//gsa:content', namespaces=NS):
        print el.attrib['name']
    
    print len(tree.xpath('//rootns:entry', namespaces=NS))
    
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