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Home/ Questions/Q 309075
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T07:42:31+00:00 2026-05-12T07:42:31+00:00

How do I form an if/else statement for a PHP function failing? I want

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How do I form an if/else statement for a PHP function failing? I want it to define $results one way if it works and another if it doesn’t. I don’t want to simply show an error or kill the error message if it fails.

Currently, I have:

if(file_get_contents("http://www.address.com")){
    $results = "it worked";}
else {
    $results = "it didnt";}
return $results
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  1. Editorial Team
    Editorial Team
    2026-05-12T07:42:31+00:00Added an answer on May 12, 2026 at 7:42 am
    if(@file_get_contents("http://www.address.com");){
        $results = "it worked";}
    else {
        $results = "it didnt";}
    return $results
    

    By prepending an @ to a function, you can surpress its error message.

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