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Asked: May 10, 20262026-05-10T22:51:27+00:00 2026-05-10T22:51:27+00:00

How do I get a DateFormat of some sort to throw an exception if

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How do I get a DateFormat of some sort to throw an exception if I try to parse an illegal date? If I parse a date like ‘99.99.9999’ with a SimpleDateFormat with the pattern ‘dd.MM.yyyy’, no exception is thrown, but this is clearly not a valid date.

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  1. 2026-05-10T22:51:27+00:00Added an answer on May 10, 2026 at 10:51 pm

    DateFormat.setLenient(false)

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