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Home/ Questions/Q 8229351
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T16:46:12+00:00 2026-06-07T16:46:12+00:00

How do I get an iterator to the next-to-last element in a STL list

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How do I get an iterator to the next-to-last element in a STL list without creating a temporary and modifying the list?
Is it possible to just say: --(--mylist.end())? Or would this change the end iterator of the list due to the prefix decrement?

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  1. Editorial Team
    Editorial Team
    2026-06-07T16:46:14+00:00Added an answer on June 7, 2026 at 4:46 pm

    Please note that in general, --mylist.end() is not guaranteed to compile for every container.

    For example, if you use a std::vector or std::array in release mode, mylist.end() is probably a raw pointer, and you cannot decrement a pointer returned by value from a function.

    A generic solution to this problem in C++11 is std::prev(std::prev(mylist.end())), after checking that the list is long enough, of course. You need to #include <iterator> for this.

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