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Home/ Questions/Q 8702487
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T02:40:02+00:00 2026-06-13T02:40:02+00:00

How do I get the required output? input string : software Company(1920 of 2012)(sb.2)(sb.3)

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How do I get the required output?

input string :

 " software Company(1920 of 2012)(sb.2)(sb.3) IBM on established (2009)"

word to be searched –

"software company(1920 of 2012)"

Output

*software Company(1920 of 2012)*(sb.2)(sb.3) IBM on established (2009) 

In short I have to find a phrase and replace the same phrase with starting and ending with asterisk (*), IGNORING THE CASE, and MATCH EXACT WORLD i

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  1. Editorial Team
    Editorial Team
    2026-06-13T02:40:03+00:00Added an answer on June 13, 2026 at 2:40 am

    You can do this easily using String#replaceAll() :

    String original =  " software Company(1920 of 2012)(sb.2)(sb.3) IBM on established (2009)";
    String subString = "software company(1920 of 2012)";
    System.out.println("New String is: " + original.replaceAll("(?i)" + Pattern.quote(subString), "*$0*"));
    

    The (?i) is added to make it case insensitive, and the Pattern#quote() is used to escape special regex characters in your substring.

    This prints:

    New String is:  *software Company(1920 of 2012)*(sb.2)(sb.3) IBM on established (2009)
    
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