Question

How do I initialize a pointer to a literal array?
I want *grid to point to the new allocated int array {1, 2, 3}.

int *grid = new int[3];
*grid = {1, 2, 3};

thank you.

Answer 1

You can’t initialize a dynamically allocated array that way. Neither you can assign to an array(dynamic or static) in that manner. That syntax is only valid when you initialize a static array, i.e.

int a[4] = {2, 5, 6, 4};

What I mean is that even the following is illegal:

int a[4];
a = {1, 2, 3, 4}; //Error

In your case you can do nothing but copy the velue of each element by hand

for (int i = 1; i<=size; ++i)
{
    grid[i-1] = i;
}

You might avoid an explicit loop by using stl algorithms but the idea is the same

Some of this may have become legal in C++0x, I am not sure.