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Home/ Questions/Q 8011847
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Editorial Team
  • 0
Editorial Team
Asked: June 4, 20262026-06-04T19:08:16+00:00 2026-06-04T19:08:16+00:00

How do I lock an object in Python? Say I have: class Foo: def

  • 0

How do I “lock” an object in Python?

Say I have:

class Foo:
  def __init__(self):
    self.bar = []
    self.qnx = 10

I’d modify foo as much as I want:

foo = Foo()
foo.bar.append('blah')
foo.qnx = 20

But then I’d like to be able to “lock” it such that when I try

lock(foo)
foo.bar.append('blah')  # raises some exception.
foo.qnx = 20            # raises some exception.

Is that possible in Python?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T19:08:17+00:00Added an answer on June 4, 2026 at 7:08 pm

    Here is a simple way of doing this.

    class Foo(object):
        def __init__(self):
            self._bar = []
            self._qnx = 10
            self._locked= False
    
        @property
        def locked(self):
            return self._locked
    
        def lock(self):
            self._locked = True
    
        @property
        def bar(self):
            if self.locked:
                return tuple(self._bar)
            return self._bar
    
        @property
        def qnx(self):
            return self._qnx
        @qnx.setter
        def qnx(self,val):
            if self.locked:
                raise AttributeError
            self._qnx = val
    
    def lock(obj):
        obj.lock()
    
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