Question

How do I make this output true and not false:

{item 1 of {4}, item 1 of {5}} = {4, 5}

I know you can do this…

{4, 5} = {4, 5}

…but I need to do something more complex.

Is that possible?

Answer 1

It probably has to do with the binding of the = operator, e.g. it gets evaluated before the lhs and rhs expressions are evaluated.

For example, this is true:

set x to {item 1 of {4}, item 1 of {5}}
x = {4, 5}