Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 589683
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T15:26:58+00:00 2026-05-13T15:26:58+00:00

How do I match the URL address in this string, I have other code

  • 0

How do I match the URL address in this string, I have other code that matches text and it seems to work, but when I try to use it here, it doesn’t, it keeps saying there is “No such file or directory. I didn’t know grep -o only worked on files?

matchString='url={"urlPath":"http://www.google.com/","thisIsOtherText"'
array=($(grep -o 'url={"urlPath":"([^"]+)"' "$matchString"))
grep: url={"urlPath":"http://www.google.com/","thisIsOtherStuff": No such file or directory

Anyway, could you please help me with matching the URL from in the “matchString” variable (it doesn’t have to use grep).

Preferred output: http://www.google.com/

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T15:26:59+00:00Added an answer on May 13, 2026 at 3:26 pm

    You need to echo the string through a pipe to grep:

    array=($(echo "$matchString" | grep -o 'url={"urlPath":"([^"]+)"'))
    

    Grep reads from a file or standard input. It doesn’t accept a string argument to search within.

    Also, grep is going to output the entire match, not the part in parentheses. You probably need to use sed.

    array=($(echo "$matchString" | sed 's/url={"urlPath":"\([^"]\+\).*"/\1/'))
    

    The sed command works like this:

    • s/// is the substitute command and its delimiters. You can use another delimiter for convenience if it makes the expression more readable or helps eliminate having to do some escapes. Between the first two delimiters is what we want to change. Between the middle one and the last one is what we want to change it to.

    • url={"urlPath":" is just the literal text we are using to help make the match

    • \( \) encloses a capture group. What falls bewteen here is what we want to snag.

    • [^"] matches any character that’s not a double-quote

    • \+ match one or more of the preceding pattern. So, in this case, that’s one or more characters that are not quotation marks.

    • .* match zero or more of any character. In this case, it starts at the quote after google.com/ and goes to the end of the string.

    • \1 outputs what was captured by the first (and only in this case) capture group.

    Visually:

    url={"urlPath":"       http://www.google.com/       ","thisIsOtherText"
    -----literal----       -------non-quote------       ---any character---
    url={"urlPath":"   \(  [^"]                    \)   .*
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 371k
  • Answers 371k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer How much searching did you do exactly? The wikipedia article… May 14, 2026 at 7:01 pm
  • Editorial Team
    Editorial Team added an answer Sometimes the values are not the same as the labels.… May 14, 2026 at 7:01 pm
  • Editorial Team
    Editorial Team added an answer load-on-startup can specify an (optional) integer value. If the value… May 14, 2026 at 7:01 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.