Question

How do I match this pattern multiple times in a string for all of them.

1=aa 2=’bb’ 3=” cc” 4=”dd”

The regex should match all these and give 4 matches as
1) 1=aa
2) 2=’bb’
3) 3=” cc”
4) 4=”dd”

I tried and so far I have this, (?<number>\d=)\s*("|')?\s*(?<value>.*?)(?=\d=)

This matches everything except the #4. It is because there is no \d= for the last one. I know I can make it optional by putting a ? at the end, but then it does not match anything correctly, what am I doing wrong.

Answer 1

The (?=\d=) part means “followed by \d=“. What you need is (?=\d=|$), which means “followed by \d= or end-of-string”:

(?<number>\d=)\s*("|')?\s*(?<value>.*?)(?=\d=|$)