Question

How do I pass an input parameter to an XSLT stylesheet? I’m using xsltproc, and I’d like to use --stringparam <param> <value> as argument, but I don’t know how to access the parameter inside the XSLT. Can someone give an example? Thanks in advance.

Answer 1

This is one I am using. The default value part is optional. You must have a

  <xsl:param name="yourParamname"/>

.

<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <!-- default value -->
<xsl:variable name="defaultDeploymentMode">
    <xsl:text>test</xsl:text>
</xsl:variable>
<xsl:param name="deploymentMode" select="$defaultDeploymentMode"></xsl:param>



<xsl:template match="/">
    <data><xsl:value-of select="$deploymentMode"/>
           </data>
     </xsl:template>