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Home/ Questions/Q 7249009
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Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T22:13:28+00:00 2026-05-28T22:13:28+00:00

How do i print out a selected field from my json object without having

  • 0

How do i print out a selected field from my json object without having to create classes for it, at the moment it prints out the whole json object but i just want to print out selected fields for example something like Console.WriteLine(response.venues.name);

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;

namespace FourSquareTest
{
class Program
{
    static void Main(string[] args)
    {
        using (var webClient = new System.Net.WebClient())
        {
            var json = webClient.DownloadString("https://api.foursquare.com/v2/venues/search?ll=40.7,-74&query=mcdonalds&client_id=XXXXXXX&client_secret=XXXXXXXX&v=20120101");
            // Now parse with JSON.Net

            JObject parsed = JObject.Parse(json);
            foreach (var pair in parsed)
            {
                Console.WriteLine("{0}: {1}", pair.Key, pair.Value);

            }

        }


    }
}
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T22:13:29+00:00Added an answer on May 28, 2026 at 10:13 pm

    Try

     JObject parsed = JObject.Parse(json);
     JToken response = parsed["response"];
     JArray venues = (JArray)response["venues"];
     JValue names = (JValue)venues[1]["name"];
    

    But I don’t have the library to test, so that’s just based on the documentation.

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