Question

How do i print out a set of integers in an args array. I intend to have an output of: The numbers are 1, 2, 3, 4, 5

System.out.println("The numbers are ");
    for(int i=0; i< args.length;i++)
    System.out.print(args[i] + " ";

The compiler gives me an error of “i cannot be resolved to a variable” When i resolve it with “int b = 0;” it gives me a single integer, rather than the integers in args

Answer 1

As of Java 5 you can also skip i entirely:

for( String arg : args )
   System.out.print(arg + " ");

Additionally, I’d like to advocate using curly braces even for one-statement blocks.
It’s easier to read and less likely to change the behavior by adding a statement (like some log statement).

Example, a naive pow() method (checks skipped for simplicity):

Orignal code:

int pow(int base, int power) { //assume power to be > 1
 int result = base;

 for( int i = 1; i <= power; i++ ) 
   result *= base;

 return result;
}

Now I’d like to log the result in each step:

int pow(int base, int power) { //assume power to be > 1
  int result = base;

  for( int i = 1; i <= power; i++ ) 
    System.out.println( base + " pow( " + i + ") = " + result );
    result *= base;

  return result;
}

Suddenly, I get a wrong result for power > 2, since now result *= base; is only executed once (it is now outside the loop).