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Asked: 2026-05-23T18:17:29+00:00

How do I process following PHP regex in Java: if(preg_match(/\r\n(.*?)\$/,$req,$match)){ $data=$match[1]; } This line

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How do I process following PHP regex in Java:

if(preg_match("/\r\n(.*?)\$/",$req,$match)){ $data=$match[1]; }

This line is part of following function, by the way:

function getheaders($req){
  $r=$h=$o=null;
  if(preg_match("/GET (.*) HTTP/"   ,$req,$match)){ $r=$match[1]; }
  if(preg_match("/Host: (.*)\r\n/"  ,$req,$match)){ $h=$match[1]; }
  if(preg_match("/Origin: (.*)\r\n/",$req,$match)){ $o=$match[1]; }
  if(preg_match("/Sec-WebSocket-Key2: (.*)\r\n/",$req,$match)){ $key2=$match[1]; }
  if(preg_match("/Sec-WebSocket-Key1: (.*)\r\n/",$req,$match)){ $key1=$match[1]; }
  if(preg_match("/\r\n(.*?)\$/",$req,$match)){ $data=$match[1]; }
  return array($r,$h,$o,$key1,$key2,$data);
}

Thanks in advance!

So far I have:

Matcher matcher = Pattern.compile("\r\n(.*?)\\$").matcher(req);
while(matcher.find()){
    data = matcher.group(1);
}

I am sure, however, that this is wrong.

Ok guys, thanks for your answers, but they did not help yet. May I ask you to tell me, however, what this regex means:

  if(preg_match("/\r\n(.*?)\$/",$req,$match)){ $data=$match[1]; }

I know, that if it does find a match with /\r\n(.*?)\$/ in the string $req, it will save the different kinds of mathces into the array $match. BUT: what is being matched here? And what’s the difference between $match[0] and $match[1]? Maybe, if I understand this, I will be able to reconstruct the way to produce equal results in Java.

Thanks Jaroslav, but:

The string I am trying to process however (the last line of the handshake sent to me by Google Chrome, is:

Cookie: 34ad04df964553fb6017b93d35dccd5f=%7C34%7C36%7C37%7C40%7C41%7C42%7C43%7C44%7C45%7C46%7C47%7C48%7C49%7C50%7C52%7C53%7C54%7C55%7C56%7C57%7C58%7C59%7C60%7C61%7C62%7C63%7C64%7C65%7C66%7C67%7C68%7C69%7C70%7C71%7C72%7C73%7C74%7C75%7C76%7C77%7C78%7C79%7C80%7C81%7C82%7C83%7C84%7C85%7C86%7C87%7C88%7C89%7C90%7C91%7C92%7C93%7C94%7C95%7C96%7C97%7C98%7C99%7C100%7C101%7C102%7C103%7C104%7C105%7C106%7C107%7C108%7C109%7C110%7C111%7C112%7C113%7C114%7C115%7C116%7C117%7C118%7C119%7C120%7C121%7C122%7C123%7C124%7C125%7C126%7C127%7C128%7C129%7C130%7C131%7C132%7C133%7C134%7C135%7C136%7C137%7C138%7C139%7C%3B%7C%3B%7C%3B%7C%3B1%3B2%3B3%3B4%3B5%3B6%3B7%3B8%3B9%3B10%3B11%3B14%3B15%3B18%3B23%3B24%3B25%3B26%3B28%3B29%3B30%3B31%3B32%3B33%3B%7C

Hey guys, I just now realize what I have been asking was irrelevant 🙁 But one answer has been right.

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1 Answer

  1. Editorial Team
    import java.util.regex.Pattern;
import java.util.regex.Matcher;

public class SplitDemo2 {

    private static final String REGEX = "/\\r\\n(.*?)\\$/";
    private static final String INPUT = "/GET (.*) HTTP/";

    public static void main(String[] args) {
        Pattern p = Pattern.compile(REGEX);
        Matcher m = p.matcher(INPUT); // get a matcher object
        int count = 0;

        while(m.find()) {
          count++;
          System.out.println("Match number "+count);
          System.out.println("start(): "+m.start());
          System.out.println("end(): "+m.end());
   }
}

    }

    More info on regex http://download.oracle.com/javase/tutorial/essential/regex/matcher.html

    Explanation of your regex 

    \r\n(.*?)\$

    \r Carriage return character.

    \n Line break character.

    (.*?) A numbered capture group

    \$ Matches a $ character.

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