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Home/ Questions/Q 6862633
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T02:41:06+00:00 2026-05-27T02:41:06+00:00

How do I remove from a map while iterating it? like: std::map<K, V> map;

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How do I remove from a map while iterating it? like:

std::map<K, V> map;
for(auto i : map)
    if(needs_removing(i))
        // remove it from the map

If I use map.erase it will invalidate the iterators

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  1. Editorial Team
    Editorial Team
    2026-05-27T02:41:06+00:00Added an answer on May 27, 2026 at 2:41 am

    The standard associative-container erase idiom:

    for (auto it = m.cbegin(); it != m.cend() /* not hoisted */; /* no increment */)
    {
      if (must_delete)
      {
        m.erase(it++);    // or "it = m.erase(it)" since C++11
      }
      else
      {
        ++it;
      }
    }
    

    Note that we really want an ordinary for loop here, since we are modifying the container itself. The range-based loop should be strictly reserved for situations where we only care about the elements. The syntax for the RBFL makes this clear by not even exposing the container inside the loop body.

    Edit. Pre-C++11, you could not erase const-iterators. There you would have to say:

    for (std::map<K,V>::iterator it = m.begin(); it != m.end(); ) { /* ... */ }
    

    Erasing an element from a container is not at odds with constness of the element. By analogy, it has always been perfectly legitimate to delete p where p is a pointer-to-constant. Constness does not constrain lifetime; const values in C++ can still stop existing.

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