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Home/ Questions/Q 4090746
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T19:16:40+00:00 2026-05-20T19:16:40+00:00

How do I return the result of the nested ajax call as the result

  • 0

How do I return the result of the nested ajax call as the result of the parent function?

//Declaring the function
var myFunction = function(myData){  
  $.ajax({
  type:'post',
  url:"/ajaxPage.php",
  data:{data:myData},
  success:function(r){
  return r;
  });
}

//Calling the function
var theResult = myFunction(myData);

I want the variable ‘theResult’ to hold the contents of the ajax call.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T19:16:41+00:00Added an answer on May 20, 2026 at 7:16 pm

    You will have to make your AJAX call synchronous (not asynchronous which is the default).

    Something like this:

    //Declaring the function
    var myFunction = function(myData){
      var returnValue = null;
      $.ajax({
      type:'post',
      async: false,
      url:"/ajaxPage.php",
      data:{data:myData},
      success:function(r){
      returnValue = r;
      });
    
      return returnValue;
    }
    
    //Calling the function
    var theResult = myFunction(myData);
    
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