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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T09:05:05+00:00 2026-05-13T09:05:05+00:00

How do I rewrite this new way to recognise addresses to work in Python?

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How do I rewrite this new way to recognise addresses to work in Python?

\b(([\w-]+://?|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/)))

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  1. Editorial Team
    Editorial Team
    2026-05-13T09:05:05+00:00Added an answer on May 13, 2026 at 9:05 am

    The original source for that states “This pattern should work in most modern regex implementations” and specifically Perl. Python’s regex implementation is modern and similar to Perl’s but is missing the [:punct:] character class. You can easily build that using this:

    >>> import string, re
    >>> pat = r'\b(([\w-]+://?|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^%s\s]|/)))'
    >>> pat = pat % re.sub(r'([-\\\]])', r'\\\1', string.punctuation)
    

    The re.sub() call escapes certain characters inside the character set as required.

    Edit: Using re.escape() works just as well, since it just sticks a backslash in front of everything. That felt crude to me at first, but certainly works fine for this case.

    >>> pat = pat % re.escape(string.punctuation)
    
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