Question

How do I select the top 10 descending totals from a column (Amount) based on another column (ID)?

This is what I’d like my desired results to look like:

(Top 1)
Row 1: ID: 9, Amount: 10, Total: 15
Row 2: ID: 9, Amount: 5, Total: 15

(Top 2)
Row 3: ID: 500, Amount: 14, Total: 14

(Top 3)
Row 4: ID: 27, Amount: 3, Total: 9
Row 5: ID: 27, Amount: 3, Total: 9
Row 6: ID: 27, Amount: 3, Total: 9 etc.

Thanks.

Answer 1

select * from t where id in 
(select top 10 id from t group by id order by sum(Amount) desc)

if you need the final results to be ordered by sum(Amount) here is a query:

select t.*,t2.sum_amount from t 
inner join (select top 10 id,sum(Amount) as sum_amount 
                 from t 
              group by id 
              order by sum(Amount) desc) t2
        on (t.Id = t2.id)
order by t2.Sum_amount desc ,id