Question

How do I show the results for $wordavg in php. I have done the query in SQL on database after taking out variables so I believe the query is correct but don’t know how to show the results of the search in php.

$usertable = 'words';
$yourfield = 'wordname'; 

$query = "SELECT AVG(CHAR_LENGTH( wordname)) AS $wordavg FROM $usertable WHERE $yourfield LIKE '"."$current_letter"."%' ";
$result = mysql_query($query);

Answer 1

First, you should be using mysqli instead. Back to your question, usually you can iterate over a result with a loop as follows:

while ($row = mysql_fetch_assoc($result)) {
    echo $row['field'];
}

More info and examples in the PHP mysql_query doc.

Since you only have one row of data to return, you don’t need the loop part. You can simply use

$row = mysql_fetch_assoc($result);
$wordavg = $row['wordavg'];

You shouldn’t have the $ in wordavg in your query. It should be just ...AS wordavg FROM...