Question

How do I sort a map of this kind:

"01" -> List(34,12,14,23), "11" -> List(22,11,34)

by the beginning values?

Answer 1

One way is to use scala.collection.immutable.TreeMap, which is always sorted by keys:

val t = TreeMap("01" -> List(34,12,14,23), "11" -> List(22,11,34))

//If  you have already a map...
val m = Map("01" -> List(34,12,14,23), "11" -> List(22,11,34))
//... use this
val t = TreeMap(m.toSeq:_*)

You can convert it to a Seq or List and sort it, too:

//by specifying an element for sorting
m.toSeq.sortBy(_._1) //sort by comparing keys
m.toSeq.sortBy(_._2) //sort by comparing values

//by providing a sort function
m.toSeq.sortWith(_._1 < _._1) //sort by comparing keys

There are plenty of possibilities, each more or less convenient in a certain context.