Question

How do I split a list of arbitrary length into equal sized chunks?

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_{See also: How to iterate over a list in chunks.
To chunk strings, see Split string every nth character?.}

Answer 1

Here’s a generator that yields evenly-sized chunks:

def chunks(lst, n):     """Yield successive n-sized chunks from lst."""     for i in range(0, len(lst), n):         yield lst[i:i + n] 

import pprint pprint.pprint(list(chunks(range(10, 75), 10))) [[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],  [20, 21, 22, 23, 24, 25, 26, 27, 28, 29],  [30, 31, 32, 33, 34, 35, 36, 37, 38, 39],  [40, 41, 42, 43, 44, 45, 46, 47, 48, 49],  [50, 51, 52, 53, 54, 55, 56, 57, 58, 59],  [60, 61, 62, 63, 64, 65, 66, 67, 68, 69],  [70, 71, 72, 73, 74]] 

For Python 2, using xrange instead of range:

def chunks(lst, n):     """Yield successive n-sized chunks from lst."""     for i in xrange(0, len(lst), n):         yield lst[i:i + n] 

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Below is a list comprehension one-liner. The method above is preferable, though, since using named functions makes code easier to understand. For Python 3:

[lst[i:i + n] for i in range(0, len(lst), n)] 

For Python 2:

[lst[i:i + n] for i in xrange(0, len(lst), n)]