Question

How do I target post_ad_cloned’s input child?

var post_ad = $('.duplicate_name'); 
var post_ad_cloned = post_ad.clone().removeClass('duplicate_name').appendTo('#sss').show();
$("post_ad_cloned input").css('color', 'red'); 

Answer 1

var post_ad = $('.duplicate_name'); 
var post_ad_cloned = post_ad.clone().removeClass('duplicate_name').appendTo('#sss').show();
$("input", post_ad_cloned).css('color', 'red'); 

or:

var post_ad = $('.duplicate_name'); 
var post_ad_cloned = post_ad.clone()
  .removeClass('duplicate_name')
  .appendTo('#sss')
  .show()
  .children('input')
    .css('color', 'red');