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Home/ Questions/Q 8020123
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T21:35:53+00:00 2026-06-04T21:35:53+00:00

How do I test if every element in a numpy array is masked? Here’s

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How do I test if every element in a numpy array is masked? Here’s what I’d like to do:

x = #is a maksed numpy array
masked_min = numpy.ma.min(x)
if masked_min IS NOT A MASKED ELEMENT:
  #do some stuff only if masked_min is a value

In practice I see this:

>>> x = numpy.ma.array(numpy.array([1,2,3]),mask=[True,True,True])
>>> masked_min = numpy.ma.min(x)
masked

Testing for masked is not helpful:

>>> numpy.ma.sum(x) == numpy.ma.masked
masked
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T21:35:55+00:00Added an answer on June 4, 2026 at 9:35 pm

    I think the most Pythonic way would be to just do what you want, and then catch any errors that result if the entire array is masked.

    For example:

    x = numpy.ma.array(numpy.array([1,2,3]),mask=[True,True,True])
    try: 
        my_min = numpy.min(x[~x.mask])
        # Continue with my_min
    except ValueError: 
        # Bail or what have you
        print 'Masks all around!'
    
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